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Update meanValueStandard1.tex #962

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18 changes: 1 addition & 17 deletions meanValueTheorem/exercises/meanValueStandard1.tex
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Expand Up @@ -9,26 +9,10 @@

What point $c$ satisfies the conclusion of the Mean Value Theorem for the function $f(x) = x^2 +x$ on the interval
$[2,6]$?
\begin{hint}
You have to find a point $c$ in $(2,6)$ such that $f'(c)=\frac{f(6)-f(2)}{6-2}$.
\end{hint}
\begin{hint}
First, compute the average rate of change of $f$ over the interval $[2,6]$,

$\frac{f(6)-f(2)}{6-2}=\answer{9}$.
\end{hint}
\begin{hint}
Next, we have to compute $f'(x)$.

$f'(x)=\answer{2x+1}$.
\end{hint}
\begin{hint}
And last, we have to solve the equation
$f'(c)=\answer{9}$.
\end{hint}
\begin{prompt}
$$c = \answer{4}$$
\end{prompt}

\end{exercise}
\end{document}
\end{document}