Solved lab

index.js

@@ -1,7 +1,126 @@
 // Iteration 1: Names and Input
+let hacker1 = "Hector";
+let hacker2 = "Maurice";
 
+console.log(`The driver's name is ${hacker1}`);
+console.log(`The navigator's name is ${hacker2}`);
 
 // Iteration 2: Conditionals
-
+if (hacker1.length > hacker2.length) {
+  console.log(
+    `The driver has the longest name, it has ${hacker1.length} characters.`
+  );
+} else if (hacker1.length === hacker2.length) {
+  console.log(
+    `Wow, you both have equally long names, ${hacker2.length} characters!`
+  );
+} else {
+  console.log(
+    `It seems that the navigator has the longest name, it has ${hacker2.length} characters`
+  );
+}
 
 // Iteration 3: Loops
+
+let spacedDriver = "";
+
+for (let letter of hacker1){
+    spacedDriver += letter.toUpperCase() + " ";
+}
+console.log(spacedDriver.trim());
+
+let reversedNavegator = "";
+for (i = hacker2.length - 1; i >= 0; i--) {
+  reversedNavegator += hacker2[i];
+}
+console.log(reversedNavegator);
+
+if (hacker1 < hacker2) {
+    console.log(`The driver's name goes first.`);
+}else if(hacker1 === hacker2){
+   console.log(`What?! You both have the same name?`); 
+}else{
+    console.log(`I, the navigator goes first, definitely.`);
+}
+
+
+// Iteration 4: Bonus 1
+let longText = `Lorem ipsum dolor sit amet, consectetur adipiscing elit. Maecenas sed pellentesque libero. 
+Nam vitae scelerisque leo, vitae pretium dolor. Phasellus gravida malesuada urna, vel dignissim 
+dolor tincidunt at. Mauris a orci eget tellus rutrum finibus vel et eu neque.
+
+Donec et nulla vel metus lacinia blandit id euismod mauris. Curabitur convallis augue eget porttitor ultricies. 
+Curabitur accumsan, magna sed dapibus auctor, ex felis congue nulla, non ornare ipsum orci non magna. Suspendisse vel 
+lorem mollis, sagittis neque quis, facilisis elit. Suspendisse et consectetur luctus sapien, at egestas 
+turpis tincidunt vitae.  
+
+In scelerisque tellus sed et neque viverra congue et. Nulla eu lobortis sem. Vestibulum viverra viverra nunc 
+id tincidunt. Phasellus tempor velit lorem, et venenatis nibh gravida. Quisque et pellentesque  velit at neque mollis finibus. `;
+
+let wordCount = 0;
+let betweenWord = false;
+let etCount = 0;
+let word = "";
+
+for (let i = 0; i < longText.length; i++) {
+  let character = longText[i];
+
+  if (
+    character !== " " &&
+    character !== "\n" &&
+    character !== "\t" &&
+    character !== "." &&
+    character !== "," &&
+    character !== ";" &&
+    character !== "?" &&
+    character !== "!"
+  ) {
+    word += character;
+    if (!betweenWord) {
+      betweenWord = true;
+      wordCount++;
+    }
+  } else {
+    betweenWord = false;
+    if (word.toLowerCase() === "et") {
+      etCount++;
+    }
+    word = "";
+  }
+}
+console.log(`world number: ${wordCount}`);
+console.log(`'et' appears ${etCount} times.`);
+
+// Iteration 4: Bonus 2
+let phraseToCheck = "Amor, Roma";
+let cleanWord = "";
+
+for (let i = 0; i < phraseToCheck.length; i++) {
+  let charact = phraseToCheck[i].toLowerCase();
+
+  if (
+    (charact >= "a" && charact <= "z") || 
+    (charact >= "0" && charact <= "9") || 
+    charact === "á" || charact === "é" || charact === "í" ||
+    charact === "ó" || charact === "ú" || charact === "ü" || charact === "ñ"
+  ) {
+    cleanWord += charact;
+  } else {
+    continue; 
+  }
+}
+
+let palindrome = true;
+
+for (let i = 0, j = cleanWord.length - 1; i < j; i++, j--) {
+  if (cleanWord[i] !== cleanWord[j]) {
+    palindrome = false;
+    break;
+  }
+}
+
+if (palindrome) {
+  console.log(`"${phraseToCheck}" is a palindrome`);
+} else {
+  console.log(`"${phraseToCheck}" is not a palindrome`);
+}