Ocelots - Kelly T #13
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kelsey-steven-ada
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Looks good! I’ve added some suggestions, let me know if there's anything I can clarify ^_^
| for (let [key,value] of Object.entries(letterCounts)) { | ||
| for (let i = 0; i < value; ++i) { | ||
| letterPool.push(key); | ||
| } | ||
| } |
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Really nice solution for ensuring we get the desired distribution of letters.
I would consider moving the creation of the letterPool variable to directly above this loop to keep it right next to where it gets used.
| const shuffle = function (letterPool) { | ||
| letterPool.sort(() => Math.random() - 0.5); | ||
| } |
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Really neat implementation 😄
| } else { | ||
| wordCount[letter] = 1; | ||
| } | ||
| } |
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Great use of frequency maps.
| if (!(key in letterBankCount)) { | ||
| return false; | ||
| } | ||
| if (wordCount[key] > letterBankCount[key]) { | ||
| return false; | ||
| } |
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If the line doesn't get too long, I suggest combining these into one if-statement so we can have one false return.
| word = word.toUpperCase(); | ||
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| let points = 0; |
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I would consider moving these lines to below scoreChart, or at least the initialization of points so they are right next to where they get used. This can make reading easier since there's no need to scroll if you have to remind yourself of what a value was initialized as.
| } | ||
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| // Calculate score for each word | ||
| for (const letter of word) { |
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Nice use of a for...of loop.
| for (const letter of word) { | ||
| points += scoreChart[letter]; | ||
| } |
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This could have an unexpected result if the string word has characters that aren't in scoreChart. If we have an input like "ABC DEF" then points will hold NaN (Not a Number) after the loop. If we wanted to skip non-alphabetic characters or characters that aren't in scoreChart, how could we do that?
| let winner; | ||
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| // Determine highestScore and winner | ||
| for (const wordEntry in scores) { |
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Nice implementation to tie break in a single loop!
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