Phoenix - Dana Delgado

adagrams/game.py

@@ -1,11 +1,129 @@
-def draw_letters():
-    pass
+import random
+
+LETTER_POOL = {
+    'A': 9, 
+    'B': 2, 
+    'C': 2, 
+    'D': 4, 
+    'E': 12, 
+    'F': 2, 
+    'G': 3, 
+    'H': 2, 
+    'I': 9, 
+    'J': 1, 
+    'K': 1, 
+    'L': 4, 
+    'M': 2, 
+    'N': 6, 
+    'O': 8, 
+    'P': 2, 
+    'Q': 1, 
+    'R': 6, 
+    'S': 4, 
+    'T': 6, 
+    'U': 4, 
+    'V': 2, 
+    'W': 2, 
+    'X': 1, 
+    'Y': 2, 
+    'Z': 1
+}
+def draw_letters(): 
+
+    # Create an empty list to hold the letters from LETTER_POOL 
+    letter_list = []
+
+    # Go through each letter and its quantities in the letter pool
+    for letter, quantity in LETTER_POOL.items():
+        # Add the letter to the list, repeating according to its quantity
+        letter_list.extend([letter]*quantity)
+
+    # Create another empty list for the letter that will be drawn
+    hand_of_ten_letters = []
+
+    # Choose 10 letters
+    for _ in range(10):
+        # Select a random index in the list
+        index = random.randint(0, len(letter_list)-1)
+        # Add the letter at the index to the list of drawn letters
+        hand_of_ten_letters.append(letter_list[index])
+        # Remove that letter from the list so we don't choose it again
+        letter_list.pop(index)
+
+    # Return the 10 drawn letters   
+    return hand_of_ten_letters
 
 def uses_available_letters(word, letter_bank):
-    pass
+
+    # Covert all letters to uppercase
+    word = word.upper()
+    letter_bank = [letter.upper() for letter in letter_bank]
+
+    # Create an empty dictionary to count the letters in the letter bank
+    available_letters = {}
+    for letter in letter_bank:
+        if letter in available_letters:
+            available_letters[letter] += 1
+        else:
+            available_letters[letter] = 1
+
+    # Check if every letter in the word is available in the letter bank and has the required quantitiy
+    for letter in word:
+        if letter in available_letters and available_letters[letter] > 0:
+            available_letters[letter] -= 1
+        else:
+            return False
+
+    return True
+
 
 def score_word(word):
-    pass
+
+    # Create a dictionary based on the score chart
+    letter_values = {
+        'A': 1, 'E': 1, 'I': 1, 'O': 1, 'U': 1, 'L': 1, 'N': 1, 'R': 1, 'S': 1, 'T': 1, 'D': 2, 'G': 2, 'B': 3, 'C': 3, 'M': 3, 'P': 3, 
+        'F': 4, 'H': 4, 'V': 4, 'W': 4, 'Y': 4, 'K': 5, 'J': 8, 'X': 8, 'Q': 10, 'Z': 10
+    }
+
+    # Covert the word to upper case
+    word = word.upper()
+    total_score = 0
+
+    # Calcualte the base score
+    for letter in word:
+        if letter in letter_values:
+            total_score += letter_values[letter]
+
+    # Add bonus pointsif the world lenght is equal or greater to 7
+    if len(word) >=7:
+        total_score += 8
+
+    return total_score
 
 def get_highest_word_score(word_list):
-    pass
+    highest_word = ""
+    highest_score = 0
+
+    for word in word_list:
+        # Get the score of the current word
+        score = score_word(word)
+
+        # If this score is higher than what we've got
+        if score > highest_score:
+            #Update the best word
+            highest_word = word
+            # Update the best score
+            highest_score = score
+        elif score == highest_score:
+            # Prefer the ten letter word if available
+            if len(word) == 10 and len(highest_word) != 10:
+                highest_word = word
+            # Prefer the shorter word if they are the same score
+            elif len(word) < len(highest_word) and len(highest_word) <10:
+                highest_word = word
+            # If both are the same lenght, choose the one that shows first in the list
+            elif len(word) == len(highest_word):
+                # Do nothing and keep the current highest word
+                continue
+
+    return (highest_word, highest_score)