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Leaves - Yitgop #41
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Leaves - Yitgop #41
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Some of this is quite well done, you do have several methods that aren't working however. Take a look at my comments and let me know if you have questions. You do seem to understand the essentials of working with linked list nodes however.
@@ -19,99 +19,228 @@ def initialize | |||
# method to add a new node with the specific data value in the linked list | |||
# insert the new node at the beginning of the linked list | |||
def add_first(value) |
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@@ -19,99 +19,228 @@ def initialize | |||
# method to add a new node with the specific data value in the linked list | |||
# insert the new node at the beginning of the linked list | |||
def add_first(value) | |||
raise NotImplementedError | |||
@head = Node.new(value, @head) | |||
end | |||
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# method to find if the linked list contains a node with specified value | |||
# returns true if found, false otherwise | |||
def search(value) |
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return true if checker.data == value | ||
checker = checker.next | ||
end | ||
return false | ||
end | ||
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# method to return the max value in the linked list | ||
# returns the data value and not the node | ||
def find_max |
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lib/linked_list.rb
Outdated
end | ||
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curr = @head | ||
self.(length-1).times do |
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This has a typo
self.(length-1).times do | |
(self.length - 1).times do | |
max = marker.data if marker.data > max | ||
marker = marker.next | ||
end | ||
return max | ||
end | ||
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# method to return the min value in the linked list | ||
# returns the data value and not the node | ||
def find_min |
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@head = curr.next | ||
else | ||
previous.next = curr.next | ||
end | ||
end | ||
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# method to reverse the singly linked list | ||
# note: the nodes should be moved and not just the values in the nodes | ||
def reverse |
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This doesn't seem to work as you never change @head
curr.next = prev | ||
prev = curr | ||
curr = temp | ||
end | ||
end | ||
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## Advanced Exercises | ||
# returns the value at the middle element in the singly linked list | ||
def find_middle_value |
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fast = fast.next.next | ||
end | ||
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return slow.data | ||
end | ||
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# find the nth node from the end and return its value | ||
# assume indexing starts at 0 while counting to n | ||
def find_nth_from_end(n) |
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fast = fast.next | ||
end | ||
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return slow.data | ||
end | ||
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# checks if the linked list has a cycle. A cycle exists if any node in the | ||
# linked list links to a node already visited. | ||
# returns true if a cycle is found, false otherwise. | ||
def has_cycle |
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This doesn't quite work as the cycle doesn't have to connect the head to the tail, it could be a circle starting toward the end. Like if the last node points to the 2nd to last node.
until curr.nil? | ||
if value >= curr.data | ||
new = Node.new(value,curr.next.next) | ||
curr.next = new |
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You'll want to leave the loop when you add the new node.
curr.next = new | |
curr.next = new | |
return |
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