TypeError in `methods(Core.Vararg)`

[yurivish]

Julia Version 1.3.1
Commit 2d5741174c (2019-12-30 21:36 UTC)
Platform Info:
  OS: macOS (x86_64-apple-darwin18.6.0)
  CPU: Intel(R) Core(TM) i9-9980HK CPU @ 2.40GHz
  WORD_SIZE: 64
  LIBM: libopenlibm
  LLVM: libLLVM-6.0.1 (ORCJIT, skylake)

julia> methods(Core.Symbol) # This works
# 6 methods for type constructor:
[1] Symbol(s::String) in Core at boot.jl:435
[2] Symbol(a::Array{UInt8,1}) in Core at boot.jl:440
[3] Symbol(s::Symbol) in Core at boot.jl:444
[4] Symbol(s::AbstractString) in Base at strings/basic.jl:205
[5] Symbol(x::Enum) in Base.Enums at Enums.jl:26
[6] Symbol(x...) in Base at strings/basic.jl:206

julia> methods(Core.Vararg) # This does not
ERROR: TypeError: in Type, in parameter, expected Type, got Vararg
Stacktrace:
 [1] signature_type(::Any, ::Any) at ./reflection.jl:767
 [2] _methods at ./reflection.jl:830 [inlined]
 [3] methods(::Any, ::Any) at ./reflection.jl:875
 [4] methods(::Any) at ./reflection.jl:890
 [5] top-level scope at REPL[24]:1

This came up in a code analyzer I'm writing which looks through symbols in lowered code (:Vararg), determines its defining module (Core), then checks whether it has any methods defined.

[ranocha]

Closes ... #34690 ...

It looks like this should have been closed by #38136?

[yurivish]

Is this PR included in 1.6 beta1? I'm having trouble using GitHub to tell (v1.5.3...v1.6.0-beta1) isn't loading) and still see the issue on 1.6 beta1.

Edit: it appears not: #39239 (comment)

[Keno]

It is not.